4[a-(3a-5)+2a]=6-a

Solution for 4[a-(3a-5)+2a]=6-a equation:

Simplifying
4[a + -1(3a + -5) + 2a] = 6 + -1a

Reorder the terms:
4[a + -1(-5 + 3a) + 2a] = 6 + -1a
4[a + (-5 * -1 + 3a * -1) + 2a] = 6 + -1a
4[a + (5 + -3a) + 2a] = 6 + -1a

Reorder the terms:
4[5 + a + -3a + 2a] = 6 + -1a

Combine like terms: a + -3a = -2a
4[5 + -2a + 2a] = 6 + -1a

Combine like terms: -2a + 2a = 0
4[5 + 0] = 6 + -1a
4[5] = 6 + -1a

Multiply 4 * 5
20 = 6 + -1a

Solving
20 = 6 + -1a

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add 'a' to each side of the equation.
20 + a = 6 + -1a + a

Combine like terms: -1a + a = 0
20 + a = 6 + 0
20 + a = 6

Add '-20' to each side of the equation.
20 + -20 + a = 6 + -20

Combine like terms: 20 + -20 = 0
0 + a = 6 + -20
a = 6 + -20

Combine like terms: 6 + -20 = -14
a = -14

Simplifying
a = -14